25x^2-36x+3=0

Solution for 25x^2-36x+3=0 equation:

25x^2-36x+3=0

a = 25; b = -36; c = +3;
Δ = b2-4ac
Δ = -362-4·25·3
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-2\sqrt{249}}{2*25}=\frac{36-2\sqrt{249}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+2\sqrt{249}}{2*25}=\frac{36+2\sqrt{249}}{50}
$